This is straight top level layers only…

#target illustrator

var docRef = app.activeDocument;

with (docRef) {

for (var i = 0; i < layers.length; i++) {

layers[i].name = i + 1;

}

}

#target illustrator

var docRef = app.activeDocument;

with (docRef) {

     for (var i = 0; i < layers.length; i++) {

          layers[i].name = layers.length - i;

     }

}

happy to have found this — thanks!!

#target illustrator

var docRef = app.activeDocument;

with (docRef) {

for (var i = 0; i < layers.length; i++) {

layers[i].name = 'ca' + (layers.length - i).toString();

}

}

Not too sure if this is what you meant or if this is the best way but I tried…

#target illustrator

var docRef = app.activeDocument;

with (docRef) {

var myNumber = 1;

for (var i = layers.length-1; i >= 0; i--) {

if (layers[i].name != 'ALWAYS') {

layers[i].name = myNumber + 'n ' + layers[i].name;

myNumber = myNumber + 1;

continue;

}

}

myNumber = 1;

}

Should number from bottom up skipping layers names 'ALWAYS'

hmmmm. sorry to bother again — is there any way to add a leading zero to the ones below ten, i.e. creating a double digit number?

thanks a million

m

Thanks Mark!

works perfect now, I had to make a small adjustment though, and set digit to 2...see below:

var docRef = app.activeDocument;

Then you don't need this line… 'var x = layers.length.toString().length;' You have hardcoded the length so you won't get 001, 011, 123 if the number of layers increases beyond 99.

No, the selection state of layers is not exposed to the Scripting model.

Ooh, that could work Larry.  I'm tied up with other work so I can't do too much research right now.

How would I address visible layers only?  Would it be in this initial statement?

Instead of:

var docRef = app.activeDocument;

It might be:

var docRef = app.activeDocument.visibility.true;

(im sure that syntax is not correct for visibility --  any advice on that attribute would be much appreciated)

thanks in advance!

Kevin,

Your guess would only test if the active document is visible But at least you got the right property name!

What Larry says; you need to test "visible" per layer. I don't have the opportunity to test it right now, but here is the last script from this thread, with a "visible" test blatantly injected where it seemed appropriate:

(I see a couple of odd programming 'choices' in this script but it might be because it evolved throughout the discussion -- a total rewrite would oblige me to test it before posting ...)

#target illustrator
 
var docRef = app.activeDocument;
 
with (docRef) {
    var myNumber = 1;
    for (var i = layers.length-1; i >= 0; i--) {
         if (layers[i].visible == true)  // <--- Testing .. 1,2,3.
         {
          var x = layers.length.toString().length;
          var z = zeroPad(myNumber);
          if (layers[i].name != 'ALWAYS') {  
               if (layers[i].name != 'GRID') {   
                    layers[i].name = z + '-' + name;
                    myNumber = myNumber + 1;
                    continue;
               }
          }
        }
    }
    // myNumber = 1;
}
 
function zeroPad(num) {
    var tmp = num.toString();
    while (tmp.length < 2) {tmp = '0' + tmp;}
    return tmp;
}
 

I'm new to scripting in Illustrator. How do I get this to run? I copy and pasted the code into a text editor and saved it with a .jsx suffix. But nothing happens when I run it in Illustrator CS6.