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jfb00
jfb00
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Static function parameter help

Apr 12, 2012 11:07 AM

Hi,

I have two functions in the same file, how can I use the first function as default value in the second function.

 

public static function get decimalFormatter1():NumberFormatter{

//

}

 

I try this:

public static function secondFunction(param1:String, param2:Int=0, param3:Function=decimalFormatter1):Array{

//

}

Getting error: -1047: Parameter initializer unknown or is not a compile-time constant.

 

Any ideas?

Thanks!

429 Views   4 Replies   Latest reply: jfb00, Apr 13, 2012 4:03 AM
 
Replies
  • GordonSmith
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    1. GordonSmith,
    Apr 12, 2012 12:32 PM   in reply to jfb00
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    decimalFormatter1 is a getter, so when you write the parameter

     

        param3:Function = decimalFormatter

     

    the default value is the result of calling the getter (i.e., it is the NumberFormatter returned by the getter); it isn't a Function. There is no way to treat a getter or setter as a Function object.

     

    Gordon Smith, Adobe

     
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  • GordonSmith
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    2. GordonSmith,
    Apr 12, 2012 12:34 PM   in reply to GordonSmith
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    As a workaround, you could use null as a default value, where null means "use decimalFormatter1". You'd write something like

     

    public static function secondFunction(param1:String, param2:int = 0, param3:Function = null):Array
    {

        var formatter:Function = null;

     

        if (param3 == null)

            formatter = decimalFormatter1;

     

        ....

    }

     
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  • jfb00
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    3. jfb00,
    Apr 13, 2012 3:23 AM   in reply to GordonSmith
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    Thanks for you reply and help Gordon.

    I am getting this error at the decimalFormatter1 line:

    -1067: Implicit coercion of a value of type mx.formatters:NumberFormatter to an unrelated type Function.

    Here is my simple get function:

    public static function get decimalFormatter1():NumberFormatter{

              var decimalFormatter:NumberFormatter = new NumberFormatter();

              decimalFormatter.rounding = "nearest";

              decimalFormatter.precision=1;

              decimalFormatter.useNegativeSign = false;

              return decimalFormatter;

            }

    Any other way?

     
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  • jfb00
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    4. jfb00,
    Apr 13, 2012 4:03 AM   in reply to GordonSmith
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    Gordon, Instead of Function I use Formatter and it works, thanks for your help!

    Best,

     
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