You could not link the class to the clip using the clip properties and instead define a clip variable in your class, and just use the clip's linkage name to instantiate different clips. Example you might have a dialog class and want to use different dialogs... you might do something like:

private var clip:MovieClip;

public function Dialog(which:int):void

{

     if(which == 1){

          clip = new simpleDialog(); //library clip

     }else{

          clip = new yesNoDialog(); //lib clip

     }

}

I guess I'm not understanding what you are (trying to) do.

I made a class:

package {

          import flash.display.MovieClip;

          public class ContentFader extends MovieClip{

                    public function ContentFader(){

                              trace("I am a contentFader instance.");

                    }

          }

}

I then made two different symbols in my library Content1 and Content2, both of which extend ContentFader. I don't get any errors and both of them call the constructor of the super class.

So what am I missing?

PS: Good habit to get into -- making class names capital.

The Class for Content1 was Content1 and its Base class was ContentFader. Likewise Content2 is Class: Content2 and Base class ContentFader.

Then just to mix it up a little. I created a Content1.as file, but none for Content2. Everything works as I would expect.

I'm guessing it is that all y'all were thinking that base class meant something other that what I think it means? If that was the case it would need to say DisplayObject or in all reality Object.

Glad that helped. You should probably figure out what it is complaining about. At work I have a lot of Flash developers. For some reason there are a group of them who never read those warning/error messages. And then at some point they are always amazed when it all breaks.

At least you are reading the messages! But do something about them sooner rather than later.