Slight enhancement. The above code fails if you have a style called 'reflect'. (Bonus points for the first -- other than Marc, Peter, John, or Uwe -- who can tell why.)

app.findGrepPreferences = null;
app.findGrepPreferences.findWhat = ".*";
l = app.activeDocument.findGrep();
s = {};
for (i=0; i<l.length; i++)
s[' '+l[i].appliedParagraphStyle.name] = 1;
r = [];
for (i in s)
r.push (i.substr(1));
alert (r);

Looking for ^. is probably more efficient than looking for ^.* since you need just one character to get a paragraph style, not the whole paragraph.

Peter

Hi,

For someone it could be important "pro" for  ^.*

I mean paraStyle applied to i.e. empty table cells to layout them with predefined format of content.

^. will exclude those, probably usefull, styles

rgds

Hi Parth

This is my solution, No greps, it probably misses something as that's what it was originally design to do see http://forums.adobe.com/message/4807305#4807305 but give it a go.

// Script to find ParagraphStyle in documents which are not just in content pasted from illustrator file
// By Trevor more than based on my script from http://forums.adobe.com/message/4807396#4807396
var   myParagraphStyle="",
        uniqueParagraphStyle = {}, n;
if (app.documents[0].stories.everyItem().textStyleRanges.length > 0) ParagraphStyleIn (app.documents[0].stories.everyItem().textStyleRanges.everyItem().appliedParagraphStyle)        
if (app.documents[0].stories.everyItem().tables.length > 0) ParagraphStyleIn (app.documents[0].stories.everyItem().tables.everyItem().cells.everyItem().textStyleRanges.everyItem().appliedParagraphStyle)
if (app.documents[0].stories.everyItem().footnotes.length > 0) ParagraphStyleIn (app.documents[0].stories.everyItem().footnotes.everyItem().textStyleRanges.everyItem().appliedParagraphStyle)
for (n in uniqueParagraphStyle) myParagraphStyle+=(uniqueParagraphStyle[n])+"\r";
alert(myParagraphStyle)
function ParagraphStyleIn (item)
    {
        var l = item.length;
        while (l--) uniqueParagraphStyle[item[l].name] = item[l].name;
     }

I expect thanks and all that with in the next few months.  Learner X is still waiting for his.

I think this method is quicker than Jongware (not to sure) when I am board in the bog I shall make up some document with a few thousand paragraphs and get the stopwatch out

Hi Jongware,

I used textStyleRanges and not paragraph (ranges) because using

.. stories.everyItem().paragraphs.everyItem().appliedParagraphStyle

will miss ...... I was at least half asleep (2:45am) when I changed the code that I wrote for finding all the used languages in a doc - which needs textStyleRanges - to this one.  For this case paragraphs is for sure better.

As you put it everyItem() is blindingly fast, Greps a so so.

The unique array function / trick I learnt from you here Thanks

http://forums.adobe.com/message/4500105#4500105

Maybe the OP will wake up either way...

Regards

Trevor