Is there any way to highlight code and make the colors show up?

Anyways, I tried what you said:

<form id="form1" name="form1" method="post" action="">
  <?php do { ?>
      <tr>
        <td><?php echo $row_getCaregiver['firstname']; ?></td>
        <td><?php echo $row_getCaregiver['lastname']; ?></td>
        <td><input name="cg_id" type="hidden" id="cg_id" value="<?php echo $row_getCaregiver['cg_id']; ?>" /></td>
        <td><?php do {
                    if($row_getEducation['cgid']= $row_getCaregiver['cg_id']){
                    echo $row_getEducation['ename'];
                    } ?></td>
      </tr>
      <?php } while ($row_getEducation = mysql_fetch_assoc($getEducation)); 
  } while ($row_getCaregiver = mysql_fetch_assoc($getCaregiver));
            ?> 
</form>

That actually works, but here is what the page shows:

Jason Couch Record 1 Record 2 Record 3 Jason Armchair

Notice: Undefined index: ename in C:\xampp\htdocs\testground\lkjlkj.php on line 93

Jason Bedding

Notice: Undefined index: ename in C:\xampp\htdocs\testground\lkjlkj.php on line 93

Line 93 is the bold part of the code above.  It looks like the code is working though.  There are only education records under the first person and not the second or third.  So what does this error mean?

Ok, after much trial and error - I found out how to write it.  It is thus:

<div>
<?php
mysql_select_db($database_localhost, $localhost);
$query_getCaregivers = "SELECT * FROM caregivers ORDER BY lastname ASC";
$getCaregivers = mysql_query($query_getCaregivers, $localhost) or die(mysql_error());
          while ($row_getCaregivers = mysql_fetch_assoc($getCaregivers)) {
                    echo $row_getCaregivers['firstname'];
                    echo $row_getCaregivers['lastname'];
                    echo $row_getCaregivers['email'];
$Caregiverid = $row_getCaregivers['cg_id'];
mysql_select_db($database_localhost, $localhost);
$query_geteducation = "SELECT * FROM  education WHERE cg_id='$Caregiverid'";
$geteducation = mysql_query($query_geteducation, $localhost) or die(mysql_error());
          while ($row_geteducation = mysql_fetch_assoc($geteducation)) {
                    echo $row_geteducation['ename'];
          }
}
?>
</div>