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Mr Clint Eastwood
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Get source path of .ai file`?

Sep 7, 2012 4:42 AM

Hi!


Have searched but i cant find a good way of retrieving the source path of the current .AI file. Is it possible?

 

IE: If i am working with a file in C:\adobe\Illustrator\beautifulfile.ai i want a function that retrieve C:\adobe\Illustrator\

 

// Clint

672 Views   6 Replies   Latest reply: pixxxel schubser, Sep 15, 2012 4:41 PM
 
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  • CarlosCanto
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    1. CarlosCanto,
    Sep 7, 2012 7:55 AM   in reply to Mr Clint Eastwood
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    alert(app.activeDocument.path);

     
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  • Muppet Mark
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    2. Muppet Mark,
    Sep 7, 2012 7:56 AM   in reply to Mr Clint Eastwood
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    Well if the file is saved some wher on system…

     

    alert( app.activeDocument.fullName.fsName );
     
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  • Mr Clint Eastwood
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    3. Mr Clint Eastwood,
    Sep 10, 2012 2:43 AM   in reply to Muppet Mark
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    Thanks!

     

    This is how i solved it!

     

     

    fullPath= app.activeDocument.fullName.fsName;                         //C:\user\fil.ai
fullPathLength= app.activeDocument.fullName.fsName.length;    // 14
docLength= app.activeDocument.name.length;                           // 6
sourcePath = fullPath.substring(0,fullPathLength-docLength);    //  C:\user\
 
 
 
     
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  • Muppet Mark
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    4. Muppet Mark,
    Sep 10, 2012 3:43 AM   in reply to Mr Clint Eastwood
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    alert( decodeURI( app.activeDocument.fullName.parent) );

     
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  • Mr Clint Eastwood
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    5. Mr Clint Eastwood,
    Sep 10, 2012 11:53 AM   in reply to Muppet Mark
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    Well, my way is better

     

     

    Thanks!

     
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  • pixxxel schubser
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    6. pixxxel schubser,
    Sep 15, 2012 4:41 PM   in reply to Mr Clint Eastwood
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    your example C:\adobe\Illustrator\beautifulfile.ai

     

     

    Well, try this:

    alert(app.activeDocument.fullName.parent.fsName);  // = C:\adobe\Illustrator
 

     

    or (if last backslash is really needed):

    alert(app.activeDocument.fullName.parent.fsName + "\u005c");  // = C:\adobe\Illustrator\
 
     
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