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Photoshop CS6 Beta (READ ONLY)

KrisHunt

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Block Eraser cursor area is ambiguous/inaccurate

Mar 22, 2012 3:11 PM

Tags: #watson

The block eraser used to make a hole exactly the size of its silhouette. Now it's completely ambiguous: the black outline of the block eraser is 15px square, and the gray outline around it is 17px square, yet it makes a 16px hole. Fix this, please!

#3145306

1507 Views 21 Replies Latest reply: Kris_Hunt, Mar 23, 2012 7:17 PM

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4,765 posts
Jan 11, 2006

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1. PECourtejoie,

Mar 22, 2012 8:40 AM in reply to KrisHunt

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Hi, Kris, is antialiasing on or off?
Is it with the default brushes?
Is your graphic display scaled by the OS?
What kind of brush preview did you select?

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2. KrisHunt,

Mar 22, 2012 8:44 AM in reply to PECourtejoie

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I don't know what you're talking about. The block eraser is never anti-aliased. It is not a brush.

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3. charles badland,

Mar 22, 2012 8:45 AM in reply to KrisHunt

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Set on Pencil Mode or Brush Mode?

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4. KrisHunt,

Mar 22, 2012 8:47 AM in reply to charles badland

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Neither; block mode!

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5. charles badland,

Mar 22, 2012 8:51 AM in reply to KrisHunt

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I'm not seeing anti aliasing on eraser in Block Mode.
I've never used it before. Is there any way to change its size?

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6. KrisHunt,

Mar 22, 2012 8:53 AM in reply to charles badland

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No, that's the entire point of the block eraser. It's different than a brush eraser in that it remains the same size relative to your screen, not the image. And it's always aliased. Very useful when dealing with pixel-precise web graphics. And now it's broken.

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7. charles badland,

Mar 22, 2012 8:56 AM in reply to KrisHunt

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Not here. It is working like how you say it should. (Mac10.6.8)

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8. KrisHunt,

Mar 22, 2012 8:58 AM in reply to charles badland

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I doubt that. Two minutes ago you didn't know it existed. Post a screenshot.

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9. charles badland,

Mar 22, 2012 9:06 AM in reply to KrisHunt

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You don't have to be a rude.... I'm trying to reproduce to help.

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10. KrisHunt,

Mar 22, 2012 9:08 AM in reply to charles badland

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Not being rude; I just doubt it. Your screenshot needs to show the block eraser next to the hole it leaves, at 100% size (mine was enlarged after the screenshot was taken so the size difference was easy to see).

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11. David__B,

Mar 22, 2012 10:09 AM in reply to KrisHunt

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Hi Kris,

I tried to recreate this but wasn't getting the behavior you described. I was testing on a Mac. I created two layers top with 50% grey fill and bottom with black. Using the eraser tool in Block mode at 100% view on the top layer it created a completely opaque cutout with no transparent pixels around the edges, for comparison I also set it to brush mode with a 20 pixel square brush right below it this did leave the transparent edge pixels as expected. I had the pixel grid on and zoomed to 1200% for the screen shot. What steps were you going through to reach this result? Were you on PC?

-Dave

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12. KrisHunt,

Mar 22, 2012 10:12 AM in reply to David__B

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Nobody said anything about leaving transparent pixels around the hole. The block eraser itself has a new semi-transparent outline around it that is 17px square, yet it leaves a crisp, 16px hole. It's ambiguous as to exactly which pixels it's going to erase. Again, your screenshot is useless unless it shows the block eraser next to it for comparison.

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13. David__B,

Mar 22, 2012 10:23 AM in reply to KrisHunt

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I think I understand, so your compliant is the appearance of the tool tool changed with CS6, so it appears to have this slightly tranparent edge now. Is that right?

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14. Noel Carboni,

Mar 22, 2012 10:23 AM in reply to KrisHunt

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Here's what it looks like in Photoshop CS5 on a Windows system:

I've just installed the beta and can confirm the same problem. Here's the same exercise as above done with CS6 and OpenGL Drawing disabled:

-Noel

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15. gimpymwmw,

Mar 22, 2012 10:21 AM in reply to KrisHunt

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Block eraser works just fine for me.

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16. Noel Carboni,

Mar 22, 2012 10:34 AM in reply to Noel Carboni

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Same problem with OpenGL enabled...

-Noel

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17. David__B,

Mar 22, 2012 10:44 AM in reply to Noel Carboni

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I see a difference in the appearance of the tool between CS5 and CS6 but don't quite understand how this change has much impact on workflow. For me personally, I generally do not work much at 100% when doing pixel level work, I usually zoom way in to where I see the individual pixels.

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18. KrisHunt,

Mar 22, 2012 10:53 AM in reply to David__B

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> I generally do not work much at 100% when doing pixel level work, I usually zoom way in to where I see the individual pixels.

Sure, but that's no excuse to let sloppiness like this slide by. Sometimes I use the block eraser tool at 100%, and now it's become competely unreliable to do so.

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19. KrisHunt,

Mar 22, 2012 10:54 AM in reply to David__B

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> I think I understand, so your compliant is the appearance of the tool tool changed with CS6, so it appears to have this slightly tranparent edge now. Is that right?

While I find the transparent border unnecessary and slightly annoying, its existence is not the problem; the problem is that the hole the eraser leaves is neither the same size of the black outline, nor the transparent gray outline.

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20. Pete.Green,

Mar 23, 2012 6:46 PM in reply to KrisHunt

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Yes, the block eraser's erased size has not been changed.

The cursor has been alterred however to include a white border outside the original black border.

In CS5, the eraser block cursor was made up of one black line on the outside and one white line on the inside so it would be visible on both black and white backgrounds. When used, the eraser would erase pixels up to the black border.

Like your image shows -> 16px for both cursors. The extra white border is not included in that 16px square.

We'll investigate into this further.

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21. Kris_Hunt,

Mar 23, 2012 7:17 PM in reply to Pete.Green

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> Like your image shows -> 16px for both cursors. The extra white border is not included in that 16px square.

Are you kidding me? Did you read the original post?

Look, here is the same image I posted earlier; except now it's at actual size. Count the pixels yourself in your favorite image editor.

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