random numbers

[Guest]

Hi i did have some code that made up a alfanumeric random number

i know it took from a list of abcdefghijklmnopqrstu0123456789

anyway i have lost it and i need a random afla-numeric does anyone know the code to do this?

[Dan_Bracuk]

Generate a random number and convert it to hex.

[Newsgroup_User]

> Generate a random number and convert it to hex.

That's not going to help with the G-Z part of the alphabet.

To the OP: why are you trying to do this?

To answer your original question:
1) create a list of valid characters, like you have
2) select a random number between 1 and [length of that list]
3) get the character from the list @ that position and store it in your
result string
4) repeat 2-3 until you have a string of the desired length.

--
Adam

[Guest]

hi Adam, that sound like what i had before, but what is the code to do this?

[Dan_Bracuk]

quote:

---

Originally posted by: JohnGree
hi Adam, that sound like what i had before, but what is the code to do this?

---

The functions randrange and listgetat, combined with the concatonation operator should work.

[Newsgroup_User]

> hi Adam, that sound like what i had before, but what is the code to do this?

Sorry mate, I rarely provide code for solutions that really oughtn't be too
far from the grasp of the person needing it. I'm a firm believer in the
"teach a person to fish" approach to problem solving. Call me a b@st@rd if
you like.

Read the docs.

Or post your code here, and we can go through where it could use
modification.

--
Adam

[insuractive]

Hex is a good call, as it will prevent any *UNFORTUNATE* letter combinations

[BKBK]

The code

<cfset rndm = lcase(replace(CreateUUID(), "-", "", "all"))>
<cfoutput>#rndm#</cfoutput>

will generate a random string of 32 characters from the list a,b,c,...,f,0,1,2,...,9. You can apply a function like left(), right() and so on, to obtain a shorter string.

[Newsgroup_User · Accepted solution]

is this the code you have 'lost'?:
http://www.cflib.org/udf.cfm?ID=529

--

Azadi Saryev
Sabai-dee.com
http://www.sabai-dee.com

[dalcde]

You can make it super complicated:

number = Math.random()*35

if(number ==10){

     number = a

} else if(number ==11){

     number = b

} else if(number ==12){

     number =c

} else if(number ==13){

     number =d

} else if(number ==14){

     number =e

} else if(number ==15){

     number =f

}

etc.

It would be super long, but it works.( number is the name of a variable )

[dalcde]

This code is also OK ( It seems that you just want a - u, change the code if you like)

        list = new Array(0, 1, 2, 3, 4, 5, 6, 7, 8, 9, "a", "b", "c", "d", "e", "f", "g", "h", "i", "j", "k", "l", "m", "n", "o", "p", "q", "r", "s", "t", "u", "v", "w", "x", "y", "z");

        character = list[Math.round(Math.random()*35];

This code is a lot more simple!

[TLC-IT]

If you have a list of letters to draw from, and don't mind if letters are repeated, then your algorithm (easily implemented in just a few lines of code) looks something like this:  (don't ask me to write it...)

1. Initialize the result-variable to an empty string.
2. Repeat the following for as many characters as you need...
   1. Select a random index in the range 0 <= n < character_list_size by calculating Trunc( Rand() * character_list_size ) where Trunc is a function that truncates to an integer and Rand is a function that returns a random floating-point number 0 <= n < 1.0.
   2. Append {the character in the list at that position} to the result.