How to solve this equation?

[fanglinyong]

can anybody help me, solve this problem in as3 ?

x+y+z=8000;

0.17*x + 0.35*y +0.08*z =960

thanks very much!!!

[Ned Murphy]

I kinda wanna lean on rusty learning and say it can't be solved... three unknowns requires three equations. 

As far as solving it with AS3, what do you mean?

[fanglinyong]

thanks for reply.somebody   like the following equation

1、x+y+z=100

2、3x+8y+1/3z=100,

used  code like this to solving the equation,but, i din't understand how to do it !!!

Sub xxx()

Dim x%, y%, z%, i%, k%

For i = 0 To 33

    For j = 0 To 12

        For k = 0 To 300 Step 3

            If i + j + k = 100 And 3 * i + 8 * j + 1 / 3 * k = 100 Then

                MsgBox "x=" & i & "y=" & j & "z=" & k

            End If

        Next k, j, i

End Sub

[_spoboyle]

AS3 for the above is

for (var i:int = 0; i < 33; i++)

{

          for (var j:int = 0; j < 12; j++)

          {

                    for (var k:int = 0; k < 300; k += 3)

                    {

                              if ((i + j + k == 100) && (3*i + 8*j + k/3) == 100)

                              {

                                        trace("x=", i, ", y=", j, ", z=", k);

                              }

                    }

          }

}

trace("done");

note 3 unknowns with 2 equations gives 2 solutions

[fanglinyong]

thanks.

but i means that how to used this code to solve my problem ??this is the key question!!!

2012-05-25

方林勇

发件人：_spoboyle

发送时间：2012-05-25 16:05

主题：[Action Script 3] How to solve this equation?

收件人："fanglinyong"<fanglinyong_81@163.com>

抄送：

Re: How to solve this equation?

created by _spoboyle in Action Script 3 - View the full discussion

AS3 for the above is

for (var i:int = 0; i < 33; i++)

{

for (var j:int = 0; j < 12; j++)

{

for (var k:int = 0; k < 300; k += 3)

{

if ((i + j + k == 100) && (3i + 8j + k/3) == 100)

{

trace("x=", i, ", y=", j, ", z=", k);

}

}

}

}

trace("done");

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[_spoboyle]

this gives a little more explanation, although doesn't actually complete for me there are too many permitations

you are also going to have to worry about the number representation issue using floating points numbers

it might be better to convert the second equations to something equivalent which uses ints

package

{

          import flash.display.Sprite;

          public class Main extends Sprite

          {

                    //x+y+z=8000;

                    //0.17 * x + 0.35 * y +0.08 * z = 960

                    public function Main()

                    {

                              // consider each equation in the form a.x + b.y + c.z = d

                              // we have 3 unknowns x, y, z so we need 3 nested for loops to run over all possibilities

                              // then the maximum value x can be is d/a

                              // maximum y = d/b

                              // maximum z = d/c

                              // now if we have 2 equations we need to take the maximum for each known from either equation

                              // so in your case with maximum x is the maximum of 8000/1 and 960/0.17 =

                              // maximum y is the maximum of 8000/1 and 960/0.35

                              // maximum z is the maximum of 8000/1 and 960/0.08

                              // all these maximums should be rounded down to the nearest integer

                              //max x = 8000

                              //max y = 8000

                              //max z = 12000

                              //we use these maximum values for the nested for loop limits

                              var maxX:int = Math.max(8000 / 1, 960 / 0.17);

                              var maxY:int = Math.max(8000 / 1, 960 / 0.35);

                              var maxZ:int = Math.max(8000 / 1, 960 / 0.08);

                              trace("max values: ", maxX, maxY, maxZ);

                              for (var i:int = 0; i < maxX; i++)

                              {

                                        for (var j:int = 0; j < maxY; j++)

                                        {

                                                  for (var k:int = 0; k < maxZ; k++)

                                                  {

                                                            // this if statement is a representation of if the values for x, y and z we are trying

                                                            // actually solve the equations

                                                            // so in your case use the following

                                                            if ((i + j + k == 8000) && (0.17*i + 0.35*j + 0.08*k) == 960)

                                                            {

                                                                      trace("x=", i, ", y=", j, ", z=", k);

                                                            }

                                                  }

                                        }

                              }

                              trace("done");

                    }

          }

}