Can I use GREP to find and replace 01 02 03 with 1 2 3?

[AlexBerryLibrary]

Hi

Can anyone provide me with the GREP search string that will allow me to quickly find and replace instances of numbers, 01 02 03 04 05 06 07 08 09 with 1 2 3 4 5 6 7 8 9?

Thanks, much appreciated.

Alex

[SJRiegel · Accepted solution]

Find

\<(0)(\d)

Replace

$2

This will find any zero followed by any digit at the start of a "word", and replace it with only the digit that follows. It leaves alone any zero in other locations (so a number like 408 or 480 would not be affected)

[AlexBerryLibrary]

Eureka! this is fantastic, beautiful even. Thanks so much.

[vinny38]

Yep, but...

[mode nitpick ON]

numbers like 024 or 0357 would also be affected. And so would be 00...

If I read carefully the request, only 01 to 09 should be grabbed.

So... maybe

Find \<(0)([1-9](?!\d))

Replace $2

[mode nitpick OFF]

[AlexBerryLibrary]

[mode bliss ON]

[SJRiegel]

Good point, vinny

I made the (perhaps faulty) assumption that all numbers with leading zeros were to be fixed ( and the double-zero situation didn't occur to me).

[Obi-wan Kenobi]

Good enough! …

(^/)