2 Replies Latest reply: Feb 12, 2014 1:00 AM by Marta_dPE RSS

    How can I store the latest member of a random list?

    Marta_dPE Community Member
    Marta_dPE Feb 11, 2014 5:04 AM

      Hi there,

       

      I need some help from you with this behaviour. I need a script to choose a random sound from a list but, each time I click the mouse on member "Speaker" the same audio should be played (only available for 3 times).

      Thanks a million. Marta

      How can I know the selected sound?

       

      ---

      global newsoundlist

       

      property thisSprite

      property myCounter

       

      on beginSprite me

        thisSprite = me.spriteNum

        myCounter = 0

      end

       

      on mouseUp()

       

        vSound = 0

         soundlist =  ["sound1", "sound2", "sound3", "sound4", "sound5"]

         vRandom = random(5)

       

      if (_mouse.mouseMember = member("speaker")) then

       

       

          myCounter = myCounter + 1

       

         

          vPlay = soundlist[vRandom]

         

          newsoundlist = [vPlay]

         

          -- sound available only for 3 times

         

               sound(1). play (member(newsoundlist[1]))

         

          if myCounter = 4 then

           

                 sound (1).stop ()

           

            _player.alert ("Sound no longer available")

           

          end if

         

         

        end if

       

       

      end mouseUp

       

        • 1. Re: How can I store the latest member of a random list?
          SeanWilson Community Member
          SeanWilson Feb 11, 2014 9:52 PM (in response to Marta_dPE)

          Try the following (attached to your "speaker" sprite):

          global newsoundlist

property myCounter
property mySoundList

on beginSprite me
  mySoundlist = ["sound1", "sound2", "sound3", "sound4", "sound5"]
  myCounter = 0
end

on mouseUp()
  if myCounter = 0 then
    -- first click, choose the sound to play
    vRandom = random(5)
    vPlay = mySoundlist[vRandom]
    newsoundlist = [vPlay]
  end if

  myCounter = myCounter + 1

  if myCounter < 4 then
    -- sound available only for 3 times
    sound(1).play(member(newsoundlist[1]))
  else
    sound(1).stop()
    _player.alert("Sound no longer available")
  end if
end mouseUp
          • 2. Re: How can I store the latest member of a random list?
            Marta_dPE Community Member
            Marta_dPE Feb 12, 2014 1:00 AM (in response to SeanWilson)

            Hi Sean,

             

            many thanks for your post, it works as i need!!