8 Replies Latest reply on Nov 24, 2014 7:29 AM by Stamm

    Get the index of the current page?

    Stamm Level 1

      Hello, I can't figure out, how to get the index of the active Page in a document. I can't use "activePage.name", as the name can not show the actual number of the current page. In the forums I found the following function to get javascripts indexOf() function.

       

      if (!Array.prototype.indexOf) { 

          Array.prototype.indexOf = function (searchElement /*, fromIndex */ ) {   

              "use strict"; 

              if (this == null) { 

                  throw new TypeError(); 

              } 

              var t = Object(this); 

              var len = t.length >>> 0; 

              if (len === 0) { 

                  return -1; 

              } 

              var n = 0; 

              if (arguments.length > 0) { 

                  n = Number(arguments[1]); 

                  if (n != n) { // shortcut for verifying if it's NaN 

                      n = 0; 

                  } else if (n != 0 && n != Infinity && n != -Infinity) { 

                      n = (n > 0 || -1) * Math.floor(Math.abs(n)); 

                  } 

              } 

              if (n >= len) { 

                  return -1; 

              } 

              var k = n >= 0 ? n : Math.max(len - Math.abs(n), 0); 

              for (; k < len; k++) { 

                  if (k in t && t[k] === searchElement) { 

                      return k; 

                  } 

              } 

              return -1; 

          } 

       

      With this I wrote then the following code:

       

      var myDocument = app.activeDocument;

      var myPages = myDocument.pages;

      var number = myPages.indexOf(myDocument.layoutWindows[0].activePage);

       

      It sadly doesn't work. When I alert "myPages" I can see, that I get the pages object. Can I know somehow get just the array with the values of this?

       

      Thank you in advance!! Appreciate any help!