Advanced XML search

[ser_g]

Hi guys,
I use this piece of code to find a current rote of my site's tree: rote = XMLSearch(rotes, "//rote[@name='roteName']");
Here I have my current rote and it's child rotes. All is fine.

Question one is: how to get this rote's parent rotes without hard coding and recursion?
Question two is: how make my search function to search the rote with one more argument? I.e. rote with argument name=roteName and argument status=visible.

Thank you,
Sergei

[Newsgroup_User]

> Question one is: how to get this rote's parent rotes without hard coding and
> recursion?

Do you mean PARENT (singular: there can be only one), or ANCESTORS?

Either way, have a look @ xpath's concept of AXES:
http://www.zvon.org/xxl/XPathTutorial/Output/example13.html


> Question two is: how make my search function to search the rote with one more
> argument? I.e. rote with argument name=roteName and argument status=visible.

You can do this:

[@colour='green' and @animal='marmoset']

This is worth reading:
http://www.w3schools.com/xpath/default.asp

--
Adam

[ser_g]

Thank you Adam,

> Do you mean PARENT (singular: there can be only one), or ANCESTORS?

I mean user is in rote news_archive and i want to build his path from homepage to news_archive.

Like: Homepage > News > Archive.

Can I somehow get this branch with a single query if I know only that my current node is "news_archive" and my root node is "root"

[ser_g]

ANCESTORS, that's right! Thank you, great link!

This one works good for me: XMLSearch(Application.rotes, "//rote[@name='ggg']/ancestor::*");