Any takers on this one?
Trying again, in shorter terms:
My company wants to run PS on a server. That server executes PS droplets automatically anytime an image is placed into a dedicated input folder. Only one person maintains the server and the droplets. The input and output images are produced and consumed by many people.
Is a single user license sufficient for this (since I am dealing with exactly 1 server) or do we need another type of license?
PS: This is similar in spirit to this: https://forums.adobe.com/message/3466847#3466847 , but for PS instead of Illustrator.
In terms of licensing, this would be considered server use. You should speak to an Adobe sales rep about licensing Photoshop for server use.
Thanks. Does anyone here have the contact info of one?
The Photoshop End User License Agreement does not permit you to develop a service based on a desktop Photoshop acting as a server. You would need to talk to an Adobe direct sales rep about a Photoshop Programmatic Use Case license, which is not available through the reseller channel. Where are you located?
Thanks for your answer! One side note: I am not using the PS as a server in the sense that it has an IP address (PS -> Edit -> Remote Connections -> Enable Remote Connections), neither am I using the SDK. I am _running_ my Photoshop desktop version on my server, which no one else has access to.
Re Location: Typically in Palo Alto, California, however, currently for several months in Singapore.
You describe a scenario where your customer accesses an automated process via a web site. This is considered a server use case, since the Photoshop instance is acting as a service to the web page.
In the CS and earlier versions of !Photoshop, there was an explicit licensing restriction against server use cases for !Photoshop. You can read the CS6 EULA here. Pay particular attention to section 2.1.7, which covers server use cases. Specifically, 220.127.116.11 prohibits "enabling web hosted workgroups or web hosted services available to the public."
Thanks a lot JLockman, will do (I marked your answer as correct).