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Well, it's a relatively simple regex , so there isn't much to verifying it. You've got the right expression for hex code 0. I'm not sure you need the brackets at this point (indicating a character class), but it's easier to start with them so that you don't need to remember them once you find other characters to exclude.
As near as I can tell, it should be what you want. You may end up wanting a more complicated regex if you find other invalid characters you want to remove (like byte order marks), but that could be done in a separate statement.